java - Input validation (do-while loop) malfunctioning - 


  ===== CS302 उपकरण बॉक्स ===== T & gt; कॉइन टॉस सिमुलेटर G & gt; ग्रेड इस्टिमेटर C & gt; रंग चुनौती Q & gt; अपनी पसंद के लिए लिखें कोड पत्र लिखें: एच अमान्य चयन कृपया प्रयास करें: टी अमान्य चयन कृपया कोशिश करें: टी

^ जब मैं प्रोग्राम चलाता हूं और इसे गलत अनुमान लगाता हूं तो मुझे मिल रहा है। उपयोगकर्ता इनपुट को मान्य करने के लिए लूप बनाया गया था, इसलिए यह पूरी तरह से असफल रहा है। मैंने गलत क्या किया है पर कोई विचार? आपके समय के लिए धन्यवाद! 

 } System.out.println ("===== CS302 टूल बॉक्स ====="); System.out.println ("T & gt; सीओआईएन टॉस सिमुलेटर"); System.out.println ("G & gt; ग्रेड इस्टिमेटर"); System.out.println ("सी & gt; रंग चुनौती"); System.out.println ("Q & gt; QUIT"); System.out.print ("अपनी पसंद के लिए लिखें कोड पत्र:"); बूलीयन code_letter; स्ट्रिंग code_choice = scanner.next (); ({Code_choice.toUpperCase ()} बराबर ("क्यू") || (code_choice.toUpperCase ()) बराबर ("सी") || (code_choice.toUpperCase ())। बराबर ("जी") || (Code_choice.toUpperCase ())। बराबर ("टी")) {code_letter = true; } Else {System.out.println ("अवैध चयन, कृपया एवियन की कोशिश करें:"); Code_letter = false; scanner.next (); }} जबकि (! (Code_letter)); {System.out.println ("आपने यह किया था?"); }}

अपने < कोड> डू-ऑयल लूप, अन्यथा चर सशर्त परीक्षण से पहले लूप के हर चलन के लिए फिर से आरम्भ नहीं होगा 

  स्ट्रिंग code_choice = scanner.next ();

इसे पसंद करें 

  // यह गुंजाइश स्ट्रिंग code_choice = null; Do not {// इसे सशर्त परीक्षण करने से पहले हर बार इसे आरंभ करें // यह पठनीयता बढ़ जाती है! Code_choice = स्कैनर.एक्सटी (); बराबर ("सी") (code_choice.toUpperCase ()। बराबर ("क्यू" .toUpperCase ())। बराबर ("टी")) {code_letter = true; } Else {System.out.println ("अवैध चयन, कृपया एवियन की कोशिश करें:"); Code_letter = false; }} जबकि (! (Code_letter));

आशा है कि यह मदद करता है!


Comments

Post a Comment

Popular posts from this blog

c# - Reactive Extensions ControlScheduler -

Well, I'm using Reactive Extension Event Handler to handle my app events, I run the headlines on the Yuri thread. I also use ControlSubular for However, recently I am getting cross thread exception despite using control scheduler and I do not know what the problem is. Code: Observable.FromEventPattern & Lt; String & gt; (CC, "UiAlertMessage", New Control Session ()) Subscribe (_ = & gt; {Alert Control. (Show this language, title, _.EventArgs.UppercaseFirst ());}); The new control scheduler (this) is not to run the code on the UI control thread, so I do not get cross threading exceptions? you should do Observable.FromEventPattern & lt; String & gt; (CC, "UiAlertMessage"). AboveOption (this). Subscribe (_ = & gt; {Alert Control. (Show this language, Titles, _.EventArgs.UppercaseFirst ());}); This is the standard way of sending a scheduler related to specific controls. Passing control scheduler as you have got subsc...
Read more

scala - Play Framework - how to bind form to a session field -

Is there any way, I can get some parameters from the header, cookies (log in userId in my case) , And then apply it in a form which I know who will deposit the ticket? SupportForm supportForm: form [supportTicket] = form (mapping ("question" -> text, "priority" -> text) (apply support ticket. (HelpText.update) What are the good practices here? What is the call to apply the request, when I can use it (and also a good practice?) Edit An issue, absolutely deceiving anyone if I were to create a hidden area with this value. It could Ript, but the issue may be re-used in any way to verify and return the form, it can not be sure how it ....
Read more

c++ - Why does Visual Studio Release build break on non-executing code line -

When I created my C ++ program with the default release configuration in Visual Studio 10, I put a breakpoint on one line Who should never be reached. What confunded me was that when the program is running then it stopped at the breaking point. Adding a volatile statement and transferring this line to the break point does not break the execution of the code where the brake appears (though does not produce the same behavior as creating a minimum project with this function). Why is the "Release Debugger" (?) Step on this line and when executing breakpoints are executed? If I keep going after the break then false statement continues to return code execution. bool bounding box :: Cutting (int32_t xpos, int32_t ypos, int32_t dx, int32_t dy) const {int32_t intersectionX; Int32_t intersections; If ((dx> 0 & amp; amp; and & amp; xpos> rights) || (dx gt; Top) || (D & LT; 0 & amp; AOPO & Lt; BOT)) Return; If (DX! = 0) {intersection Y = ypos + (left...
Read more