regex - bash: String Operator with regular expression -

I want to list all the files in my home folder, and # < / Code> in the file name. For example: # emacs # to .emacs

This is my code

 < Code> should be printed as $ {ls ~} in dir # trim trailing trailing filename = "$ {dir # \ #}" echo $ {filename} done  

but it Even though # was still managing the regular expression $ {dir # \ #} in the terminal

Can you tell me that my code Where's the smell?

Remove # should be the filename,

< In some systems (such as Solaris) does not work on the command, you need to avoid it: pre> filename = "$ {dir //}"

  filename = "$ {dir // \ # /}"  

The rest are fine for both Saigwin and Solaris.

If you need to delete all content before # then

  filename = "$ {dir ## * #}"  

If you need to remove all content after the #

  filename = "$ {dir %% # *}"  

, here The full explanation is that I am copying and pasting bash substring replacement

  $ {string / substring / replacement} and $ substring $ substation with $ substring first match Replace. $ {String // Substring / Replacement} $ $ String% substring matches $ substring $ match with at least $ substring from the back of the string. $ {String %% substring} $ {String # substring} deletes the longest match of the $ substring behind the $ string, removes at least the match of the $ substring against the $ string. $ {String ## substring} $ removes longest match of substring from front of string.