python - How to generate index.rst alone or generate everything excluding conf.py by sphinx-apidocs? -

I understand that creating RRT for all the following modules, except index.rst

< Pre> Sphinx-apidoc -f -o lot_good_dex / very-good

and everything below, which contains index.rst, conf.py, Makefile, etc.

  sphinx-pdok-f-f-o-lot-good_dex / very good  

The problem is that the Sphinx-APIID is not confp correct Produces, so always include me to confp man Must correct modify the sys.paths if I modify my Python code in the "Very Good" folder, then I should run the sphinx-opidoc command without "-F", so conf.py was preserved. is. However, if I add new module directly to a very disturbance, index.rst is not updated without "-F" option, which means that my new module will not be in the doctor. I believe that either a person only generates the index.rst file, or using the "- F" option without overwriting the confaj. Is there any way to do this?

This is just some experience.

My approach is to use a custom config.py and always specifies that I sphinx-build -F With options This way my config.py "is not overwritten, even if something new (and worthless) config.py has been created.

To specify a custom config.py you should use the -c option as described in the document:

 < Code> -c path in the source source directory .py, but use the given configuration directory. Note that other files and paths provided by the configuration values ​​are expected to be relative to the configuration directory, so they must also be present at this location. The new  

command in version 0.3 will look like this:

  Sphinx-Build-B HTML-C% Sphinx Config Dyier %% Source Code %% Build Dior %  

Hope it helps.