php - my IF statement not working as expected -


मैंने अपनी समस्या का एक सरल उदाहरण नीचे लिखा है: 

  & lt;? Php if ($ SpType == "SPI") {? & Gt; & lt; div id = "mainImageInside" & gt; & Lt;? Php echo $ sSeries? & Gt; & Lt;? Phpif ($ sSeries == 4) {? & Gt; & lt; div id = "buDepth" वर्ग = "फ़ॉन्ट" & gt; काम किया & lt; / div & gt; & lt;? Php}? & Gt; & Lt; / div & gt; & lt;? Php; ? & Gt;

$ sSeries को 3 पर सेट किया गया है, जब मैं इसे गूंजता हूं, तो मुझे 3 स्क्रीन पर प्रिंट किया जाता है, यदि I बयान से 4 की उम्मीद होती है, इसलिए इसे प्रिंट नहीं करना चाहिए हालांकि पाठ "काम" किया गया है, अगर पाठ 3 या 4 के रूप में सेट किया गया है, तो यह टेक्स्ट "काम" पर कोई फर्क नहीं पड़ता, क्या कोई मुझे इस के साथ मदद कर सकता है? 

  & lt; php अगर ($ spType == "पोस्ट-पाठ" itemprop = "text"> 
 डीबग करने के लिए एक लाख गुना अधिक पठनीय है (कम से कम मेरे लिए) एसपीआई ") {गूंज '& lt; div id =" mainImageInside "& gt;' । $ SSeries; यदि ($ sSeries == 4) {echo '& lt; div id = "buDepth" class = "font" & gt; काम किया & lt; / div & gt;'; } गूंज & lt; / div & gt; '; }? & Gt;

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