regex - Insert a space after every given character - java -


I need to insert a location after a given character in the string.

For example "Abc.def ..."

need to be created "abc def ..."

Then given in this case

My search on Google did not answer that question

I really need to get some serious reggae knowledge.

Edit: ---------------------------------------- ---------- -------

  string testing = "0:; 1:;"; Test.replaceAll ("\\:", "::" "); Println (test); // Output: 0 :; 1:: // Not done anything  

Solution: ------------------------------- ------------------- -----

  string testing = "0:; 1:; "; ** test = ** test.replaceAll (" \\: ",": "); Println (test);  

You can use:

  string input = "abc.def ..."; string result = input.replaceAll (" \\. ",". "); // Results" abc. Def ".  

Edit:

  string testing =" 0:; 1:; "; Results = test.replaceAll (": ",": "); // The result will be" 0:; 1:; "(Testing is still unmodified)  

Edit:

As stated in the other answer, String.replace () < / Code> All you need is a simple replacement only if it is a regular expression (as you said in your question), then you have to use String.replaceAll () .


Comments

Popular posts from this blog

ios - How do I use CFArrayRef in Swift? -

eclipse plugin - Run java code error: Workspace is closed -

c - Error on building source code in VC 6 -